#11766 - Datch - Sat Oct 18, 2003 5:11 pm
Not really limited to GBA but anyway...
I would like to know how to calculate the new x,y of a point when drawn in pespective.
Here's a sample :
[Images not permitted - Click here to view it]
A(6,2) => A'(6,5)
B(6,4) => B'(6,8)
C(6,8) => C'(6,12)
D(6,12) => D'(6,14.5)
It's easy to figure out this way that to every single point in the first rectangle there is a corresponding point in the perspective trapeze. I just would like to know how to figure out the new coordinates of the points.
I've made a lot of searches on Google but I can't figure out a combination of key words that will bring me a page with the answer. So in a last attempt I'm asking you. Any hint will be appreciated!
_________________
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Last edited by Datch on Sat Oct 18, 2003 6:26 pm; edited 1 time in total
I would like to know how to calculate the new x,y of a point when drawn in pespective.
Here's a sample :
[Images not permitted - Click here to view it]
A(6,2) => A'(6,5)
B(6,4) => B'(6,8)
C(6,8) => C'(6,12)
D(6,12) => D'(6,14.5)
It's easy to figure out this way that to every single point in the first rectangle there is a corresponding point in the perspective trapeze. I just would like to know how to figure out the new coordinates of the points.
I've made a lot of searches on Google but I can't figure out a combination of key words that will bring me a page with the answer. So in a last attempt I'm asking you. Any hint will be appreciated!
_________________
Visit SR-388 now and get a 40% discount!
Last edited by Datch on Sat Oct 18, 2003 6:26 pm; edited 1 time in total